1)
Calculate the number of moles of Chlorine using the gas equation
PV =nRT
where n = no. of moles of chlorine
(785 torr)(0.155L) = n(62.36 L torr K-1mole-1)(273+25)K
n = (121.675)/(18583.28)
n = 0.006548 mole
The reaction is as
From the reaction, it is clear that 1 mole of MnO2 produces 1 mole of chlorine.
Therefore, No. of moles of MnO2 = moles of chlorine = 0.006548 mole
Mass of MnO2 = (No. of moles of MnO2)(Molar mass of MnO2)
= (0.006548 mole)(118.93 g/mole)
= 0.7787 g
= 0.779 g (Ans)
1. 2. Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with...
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Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as described by the chemical equation MnO,(s) + 4 HCl(aq) + MnCl(aq) + 2H,0(1) + Cl (8) How much. Mno,(s) should be added to excess HCl(aq) to obtain 155 mL CI(8) at 25 °C and 1.00 x 10 kPa? mass: g MnO Question Source MRG-General Chemistry | Publisher
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