Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid,...

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Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as described

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Answer 1

Answer #1

Given:

P = 785 torr

= (785/760) atm

= 1.0329 atm

V = 285 mL

= (285/1000) L

= 0.285 L

T = 25.0 oC

= (25.0+273) K

= 298 K

find number of moles using:

P * V = n*R*T

1.0329 atm * 0.285 L = n * 0.08206 atm.L/mol.K * 298 K

n = 1.204*10^-2 mol

This is number of mol of Cl2 formed

From reaction,

Mol of MnO2 required = mol of Cl2 formed

= 1.204*10^-2 mol

Molar mass of MnO2,

MM = 1*MM(Mn) + 2*MM(O)

= 1*54.94 + 2*16.0

= 86.94 g/mol

use:

mass of MnO2,

m = number of mol * molar mass

= 1.204*10^-2 mol * 86.94 g/mol

= 1.047 g

Answer: 1.05 g

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Answer 2

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