Question

You may want to reference (Page) Section 6.4 while completing this problem Part A How much heat must be absorbed by a 200 g sample of water to raise its temperature from 16.0°C to 50.00 (For water, C.-4.18J/"C.) Express your answer to three significant figures and include the appropriate units. Value Units Submit Rest Answer

Answer 1

We know the fromula

q = m.c.$\Delta$T

Where

q = heat absorbed

m = mass of the sample = 20.0 g

c = specific heat of substance = 4.18 J/g.⁰C

$\Delta$T = change in temperature = final temperature - initial temperature

So lets solve above formula with given values , we get

Heat absorbed

q = 20.0 g $\times$ 4.18 J/g.⁰C $\times$ (50.0 - 16.0) ⁰C

= 2842.4 J

= 2.84 kJ

So our answer is 2.84 kJ