Consider again the hypothetical population with two genes, each with two alleles (A & a, B...
Consider again the hypothetical population with two genes, each with two alleles (A & a, B & b) as in question 6. If you perform a monohybrid cross of an AABB homozygote with an aabb homozygote, what is the proportion of F2 offspring that have the genotype AaBb? a.0.0625 b.0.125 c.0.5 d.0.25
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Consider again the hypothetical population with two genes, each
with two alleles (A & a, B...
3. Consider two traits for a hypothetical animal fur color and ear length. Each trait is...
3. Consider two traits for a hypothetical animal fur color and ear length. Each trait is controlled by one gene with two alleles. Black fur is dominant to gray fur and long ears are dominant to short. The genes for the two traits are located on different chromosomes. Note: In the following problems, you need to take both traits into account simultaneously a. You cross a true breeding black long-eared male with a true-breeding gray short-eared female. What is the...
Linkage: Consider three genes, each with two alleles. An individual with genotype AAbbDD is crossed with...
Linkage: Consider three genes, each with two alleles. An individual with genotype AAbbDD is crossed with an individual whose genotype is aaBBdd. What are all the gamete types (gamete genotypes) that their offspring (AaBbDd) can produce? Draw chromosome diagrams if it helps you to answer the question. a. If the three genes are unlinked? b. If all three links are tightly linked (no crossing over)? c. If the first two genes are tightly linked (no crossing over), but the third...
Consider a locus with two alleles - A and a. These alleles are codominant, meaning that...
Consider a locus with two alleles - A and a. These alleles are codominant, meaning that the fitness of the heterozygote is halfway between either homozygote. Consider further a population of randomly mating green frogs where the genotype counts are AA = 500, Aa = 250, and aa = 250. In this population the relative fitnesses of each genotype are AA = 1.00, Aa = 0.80, and aa = 0.60. What is the mean relative fitness within this population? Please...
Consider a locus with two alleles - A and a. These alleles are codominant, meaning that...
Consider a locus with two alleles - A and a. These alleles are codominant, meaning that the fitness of the heterozygote is halfway between either homozygote. Consider further a population of randomly mating green frogs where the genotype counts are AA = 500, Aa = 250, and aa = 250. In this population the relative fitnesses of each genotype are AA = 1.00, Aa = 0.80, and aa = 0.60. What is the mean realtive fitness within this population? Please...
Consider a locus with two alleles - A and a. These alleles are codominant, meaning that...
Consider a locus with two alleles - A and a. These alleles are codominant, meaning that the fitness of the heterozygote is halfway between either homozygote. Consider further a population of randomly mating green frogs where the genotype counts are AA = 500, Aa = 250, and aa = 250. In this population the relative fitnesses of each genotype are AA = 1.00, Aa = 0.80, and aa = 0.60. What is the expected allele frequency change for A after...
Consider a locus with two alleles - A and a. These alleles are codominant, meaning that...
Consider a locus with two alleles - A and a. These alleles are codominant, meaning that the fitness of the heterozygote is halfway between either homozygote. Consider further a population of randomly mating green frogs where the genotype counts are AA = 500, Aa = 250, and aa = 250. In this population the relative fitnesses of each genotype are AA = 1.00, Aa = 0.80, and aa = 0.60. What is the expected allele frequency change for A after...
Assume that tail length in mice is a quantitative trait involving two genes, each with 2...
Assume that tail length in mice is a quantitative trait involving two genes, each with 2 alleles. One allele at each gene contributes to long tails, the other allele at each gene does not (small tails). The genes are located on different autosomes. Mice with 0 contributing alleles have tails that are 4 cm in length; mice with tails with 4 contributing alleles are 12 cm in length. Determine the phenotypic ratio from an F2 from a true breeding parent...
Genes A and B are linked. Individual plants homozygous for different combinations of these genes (AABB,...
Genes A and B are linked. Individual plants homozygous for different combinations of these genes (AABB, aabb, AAbb, aaBB) were crossed at random to produce F1 plants. The F1 plants were self pollinated to produce the F2. The F2 progeny from six of the F1 self pollinations are listed below. Number of F2 plants in each phenotypic class F1 Plant-------------------AB--------------- Ab --------------- aB----------------- ab 1 --------------------------0 ----------------98 ---------------- 0------------------ 32 2 ------------------------- 64 --------------10 -----------------8...
In sweet peas, two genes (genes A and B) control flower color. The dominant alleles of...
In sweet peas, two genes (genes A and B) control flower color. The dominant alleles of both genes produce enzymes that function in the biochemical pathway shown to convert colorless precursors to a purple pigment. The recessive alleles do not produce enzyme. Therefore, at least one dominant allele of both gene A and gene B are required for purple flowers. Answer the questions about this biochemical pathway. ΑΑ, Αα BB, Bb Enzyme A Enzyme B Colorless precursor 1 Colorless precursor...
A Better Way? As you can see, Punnett squares for phenotypes that involve several genes can...
A Better Way? As you can see, Punnett squares for phenotypes that involve several genes can get complicated. If you can recognize the patterns, you can make a mathematical model to figure out how common or rare a particular genotype or phenotype would be, depending on the number of genes involved. To do this, you begin by figuring out how many different combinations of alleles each Fparent could contribute to the F2 generation. When one gene-A-was involved, each parent could...
3. Consider two traits for a hypothetical animal fur color and ear length. Each trait is controlled by one gene with two alleles. Black fur is dominant to gray fur and long ears are dominant to short. The genes for the two traits are located on different chromosomes. Note: In the following problems, you need to take both traits into account simultaneously a. You cross a true breeding black long-eared male with a true-breeding gray short-eared female. What is the...
Consider a locus with two alleles - A and a. These alleles are codominant, meaning that the fitness of the heterozygote is halfway between either homozygote. Consider further a population of randomly mating green frogs where the genotype counts are AA = 500, Aa = 250, and aa = 250. In this population the relative fitnesses of each genotype are AA = 1.00, Aa = 0.80, and aa = 0.60. What is the mean realtive fitness within this population? Please...
In sweet peas, two genes (genes A and B) control flower color. The dominant alleles of both genes produce enzymes that function in the biochemical pathway shown to convert colorless precursors to a purple pigment. The recessive alleles do not produce enzyme. Therefore, at least one dominant allele of both gene A and gene B are required for purple flowers. Answer the questions about this biochemical pathway. ΑΑ, Αα BB, Bb Enzyme A Enzyme B Colorless precursor 1 Colorless precursor...
A Better Way? As you can see, Punnett squares for phenotypes that involve several genes can get complicated. If you can recognize the patterns, you can make a mathematical model to figure out how common or rare a particular genotype or phenotype would be, depending on the number of genes involved. To do this, you begin by figuring out how many different combinations of alleles each Fparent could contribute to the F2 generation. When one gene-A-was involved, each parent could...
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