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In sweet peas, two genes (genes A and B) control flower color. The dominant alleles of both genes produce enzymes that functi
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1. AaBb genotype class has purple flowers.

2. Аавь (АВ) (АБ) ав аb) AABB ААВЫ Аавв| Аавь АВ ААВ БААББ Аавь Аарь Ah ло» лапыловы анын таань AaBb (B) AaBB AaBb aaBb aaBb AaB

The punett square of the dihybrid cross shows that :

No of phenotypes showing purple flowers- 9

No of phenotypes showing white flower - 7

So the ratio is 9:7

3. AaBb x aabb ab ab ab ab AB I AaBb | AaBb AaBb Aa Bb Ab Aabb | Aabb Aabb Aabb ab aabb I aabb aabb aabb a Breda aabb aaBb aaBb

The punett square represents the dihybrid cross between AaBb x aabb

No of genotypes in one punett square= 16

No of total offsprings =100

No of genotypes in 100 offsprings= 100/16= 25/4

No of genotypes in punett square showing white flower= 12

No of offsprings showing the same genotype= 12 x 25/4 = 75

Therefore, 75 offsprings out of 100 are expected to bear white flowers.

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