Question

Explain how the following bond lengths (in picometers) provideevidence for the existance of delocalized orbitals...

Explain how the following bond lengths (in picometers) provide evidence for the existance of delocalized orbitals in the carbonate ion: C-O (average) 143; C=O (average) 122; in CO32- 129. Select all that apply.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Bmd ongth 122 pm Len gth Bond 143 Pm 129 pm in Co2- Three honm passible &tsuctures aru bmds ar twu types f in Cc-o) here ther

Add a comment
Know the answer?
Add Answer to:
Explain how the following bond lengths (in picometers) provideevidence for the existance of delocalized orbitals...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Question 10 Which of the following molecules are stabilized by delocalized it orbitals? Select all correct...

    Question 10 Which of the following molecules are stabilized by delocalized it orbitals? Select all correct answers. یہ بلدي هم= O molecule a O molecule b moleculec molecule d

  • Calculate the bond dissociation energy 2 HF + CO2COF2 + H2O , using table We were...

    Calculate the bond dissociation energy 2 HF + CO2COF2 + H2O , using table We were unable to transcribe this imageTable 8.7 Some Average Single- and Multiple-Bond Lengths in Picometers (pm)* SINGLE BOND LENGTHS GROUP 1A 4A 5A 6A ZA 4A 5A 6A ZA ZA | H I Nor I si Isa | Br 74 110 9894 145 138 132 127 142 ZA | 161 154 147 143 141 194 187 181 176 191 210 140136 1 134 187 180...

  • 13. In the molecular orbital model of benzene, how many pi electrons are delocalized about the...

    13. In the molecular orbital model of benzene, how many pi electrons are delocalized about the ring? A) 2 в) з C) 4 D) 5 E) 6 14, In the molecularorinl model of benzene,ow manypi electrons are in bonding molecular orbitals? A) 6 B) 5 C) 4 D) 3 E) 2 15. Cyelopentadiene is unusually acidic for a hydrocarbon. An explanation for this is the following statement A) The carbon atoms of cyclopentadiene are all sp'-hybridized B) Cyclopentadiene is aromatic....

  • Part A. Which of the following is the strongest bond? C≡C, C–O, C–N, C–C, C=C . What is the average bond order for a CO...

    Part A. Which of the following is the strongest bond? C≡C, C–O, C–N, C–C, C=C . What is the average bond order for a CO bond in the carbonate ion? :0 Ö: 2

  • 12. What is the hybridization of the central atom in each of the following? (a) BeH2...

    12. What is the hybridization of the central atom in each of the following? (a) BeH2 (b) SF6 (c) PO43- (d) PCl5 16. Two important industrial chemicals, ethene, C2H4, and propene, C3H6, are produced by the steam (or thermal) cracking process: 2C3 H8(g) ⟶ C2 H4(g) + C3 H6(g) + CH4(g) + H2(g) For each of the four carbon compounds, do the following: a) Draw a Lewis structure. b) Predict the geometry about the carbon atom. c) Determine the hybridization...

  • can someone explain everything on how to draw partia orbitals and why these are the answers!!!...

    can someone explain everything on how to draw partia orbitals and why these are the answers!!! three-dimensional geometry. or ul no nyurogeell atois alnu Cicany SIOW a. H;O* (hydronium ion) b. CN (cyanide ion) Both carbon and nitrogen are sp sp н- hybridized sp lone pair sp lone pair Н Hi, c. CNH3 (formaldehyde imine) d. H;C=C=O (ketene) Н. 9 H, Lone pairs are in sp? Lone pair is in sp? O'H Nitrogen and Carbon are both sp? Terminal carbon...

  • sos 1. The O-C-O bond angle in the CO32-ion is approximately A. 90° B. 109.5 Trigonal...

    sos 1. The O-C-O bond angle in the CO32-ion is approximately A. 90° B. 109.5 Trigonal geometry (C.)120° D. 180° E. 60° will have bond angles of 109° 2. Of the following species, A. PO4 B. CIF3 C. CCl4 D. NH3 E. All of these will have bond angles of 1090 3. The basis of the VSEPR model of molecular bonding is A. regions of electron density on an atom will organize themselves so as to maximize s-character B. regions...

  • b) Is CO paramagnetic or diamagnetic? What is the bond order of CO? c) Draw a Lewis structure...

    Draw an energy-level diagram for the valence molecular orbitals of CO. Include the relevant atomic orbitals in your diagram. Clearly label each molecular orbital (e.gs2s, p2p, etc.) and fill in the appropriate number of electrons. Use the same energy order as the neutral O2 molecule.b) Is CO paramagnetic or diamagnetic? What is the bond order of CO? c) Draw a Lewis structure for CO. Does this match the predicted bond order? d) CO can react withOH– to form the formate...

  • 1.5 pts Question 17 How do the C-S bond lengths in CS32 compare? Two are the...

    1.5 pts Question 17 How do the C-S bond lengths in CS32 compare? Two are the same length, the other is longer. Two are the same length, the other is shorter. They are all different lengths. They are all same length. Not enough info to tell. 1.5 pts D Question 18 Which of the following molecules or ions: SeO2, SeO3, Se032, will exhibit resonance structures ? SeO2. Seos, and Seo,2- Seo, only SeO2 and Seo, only SeOg and SeO32- only...

  • please help in all sections asap! The following two drawings are resonance structures of one compound....

    please help in all sections asap! The following two drawings are resonance structures of one compound. a-o But the following two drawings are not resonance structures Not resonance structures They are, in fact, two different compounds. Choose the correct explanation(s). Select all that apply. Benzene does not have three C-C single bond and three C-C double bonds. In fact, all six C-C bonds of the ring have the same bond order and same length. Benzene have three C- single bond...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT