Question

ion 1, fi 3. Draw a sample of X from question 2 and below is the data set: 1 1.5 2.1 2.6 1.9 a. Find the mean and standard deviation of the sample. b. Calculate the confidence interval of the mean. c. Perform a t test to test if the mean equals 2 or not.

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Answer #1

a) Here

sample mean ar{x} = 1.82

sample standard deviation s-0.606

and sample size 5

b) a 95% confidence interval for true mean

(7 *to.025,n-1 Vn *to.o25,n-1,T+ V n +m

0,00to.os.4 vS 0.025,4 0.025.4, 1.8240506 = ( 1.82--* t0.025.4, 0.025,4 1.O4

0.606 = (1.82 * 2.77645, 1.82+ * 2.77645, 1.82606 2.77645)

1.06755, 2.57245)

c) To test H_0:mu = 2 against H_1:mu eq 2

The test statistic can be written as

Vn(T - 2) which under H0 follows a t distribution with n-1 df.

We reject H0 at 5% level of significance if obs| ノ 10.025, n-1

Now,

The value of the test statistic tobsー-0.664179

and critical value 0025.4 2.77645

Since tbs-0.664 179メt0.025.4 2,77645 , so we fail to reject H0 at 5% level of significance and we can conclude that the true mean is not significantly different from 2.

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