Using the dataset that you used for the midterm (Find it on the Blackboard), do the following:
1) (4 points) Submit the values for items a to e in the table below: mean, sample size, standard deviation, and 95% confidence interval for mean. (SPSS Command: Analyze/Descriptive Statistics/Explore)
Variable |
Statistic |
||
Height |
Mean |
71.2 |
|
Sample Size N |
999 |
||
Standard Deviation |
2.913 |
||
95% Confidence Interval for Mean |
Lower Bound |
71.02 |
|
Upper Bound |
71.38 |
2) (4 points) Assume that you want to test whether the average height (the population mean μ) is less than 72 inches. Write down in both symbols and words the null hypothesis and alternative hypothesis.
2) (6 points) What type of significance test should you use to test your hypothesis? Write down the test statistic formula, and calculate the value of the test statistic. (Hint: Plug the sample standard deviation into the test statistic formula in place of the population standard deviation.)
3) (4 points) Find the P-value. [Use Table A: Standard Normal probabilities]
4) (3 points) At level of significance of 0.05 (5%), explain what conclusion you can draw about the hypothesis.
5) (8 points) Use SPSS to conduct the following significance test: H0: μ =72 vs. Ha: μ≠72. [Use SPSS Analyze/Compare Means/One Sample T-test/Set Test Value to 72.] What type of significance test is this? Report the value of the test statistic (“t”-statistic) and the corresponding P-value (“Sig.” level) that SPSS provides. Suppose the level of significance you chose for your test is the conventional 0.05 (5%), explain what conclusion you can draw about the hypothesis.
Using the dataset that you used for the midterm (Find it on the Blackboard), do the following: 1) (4 points) Submit the values for items a to e in the table below: mean, sample size, standard deviatio...
A sample mean, sample size, and population standard deviation are provided below. Use the one-mean z-test to perform the required hypothesis test at the 10% significance level. x=37, n = 31, σ=9, H0 : μ=39, Ha: μ<39 EB Click here to view a partial table of areas under the standard normal curve. The test statistic is z- (Round to two decimal places as needed.)
sample mean = 213.4552 sample Standard deviation = 44.81542 N=50 alpha = .05 SEM = 6.337857477 For each of the following hypothesis testing problems, manually calculate the t-statistic, use the 5% level of significance (alpha = 0.05), determine the rejection region, determine the p-value of the t-test, use the 95% confidence interval in part (c) to make a decision about whether or not to reject the null hypothesis. Test the null hypothesis that the true mean is 225 versus the...
A sample mean, sample size, and population standard deviation are given. Use the one-mean z-test to perform the required hypothesis test at the given significance level. Use the P-value approach. x̄ = 259, n = 15, σ = 19, H 0: μ = 250, Ha : μ > 250, α = 0.01
A sample mean, sample size, and sample standard deviation are provided below. Use the one-mean t-test to perform the required hypothesis test at the 1% significance level. x=22 s=6 n=15 H0: M=24 Ha: M<24 The test statistic is t=
section 9.5 A sample mean, sample size, and sample standard deviation are provided below. Use the one-mean t-test to perform the required hypothesis test at the 5% significance level x = 23, s = 6, n = 32, Ho H = 27, H.: H = 27 Click here to view a partial table of values of The test statistic ist=Q (Round to two decimal places as needed.) A sample mean, sample size, and sample standard deviation are provided below. Use...
A sample mean, sample size, and sample standard deviation are provided below. Use the one-mean t-test to perform the required hypothesis test at the 5% significance level. x:30, s-8, n:32. HOP:30, Ha:p>30 EE Click here to view a partial table of values of ta The test statistic is t Round to two decimal places as needed) The P-value is the null hypothesis. The data sufficient evidence to conclude that the mean is
a sample of 106 body temperatures has a mean of 98.20 oF and a standard deviation of 0.62 oF. use a 0.05 significance level to test the claim that the mean body temperature of the population is equal to 98.6 oF, as is commonly believed. Find the following: A. Original claim: B. Opposite claim: C. alternative and Null Hypothesis: D. significance level: E. test statistic: F. P-vaule G. reject or fail to reject: H. final conclusion:
A sample mean, sample standard deviation, and sample size are given. Use the one-mean t-test to perform the required hypothesis test about the mean, μ, of the population from which the sample was drawn. Use the critical-value approach. 7. x-20.8, s-7.3>, n = 11, Ho: μ = 18.7, Ha: μ # 18.7, α = 0.05 a. Test statistic: t = 0.95. Critical values: ±1.96. Reject Ho. There is sufficient evidence to b. Test statistic: 0.95. Critical values: t = ±2.201....
5. [18 points] Consider the Minitab output shown below. Test of μ = 100 vs > 100 The assumed standard deviation 2.4 95% Lower Bound 100.770 Mean SE Mean 101.560 3.25 25 a. Fill in the missing values in the output. Can the null hypothesis be rejected at the 0.0s level? Why? b. Is this a one-sided or a two-sided test? C. If the hypotheses had been Ho: μ = 99 versus H : μ > 99, would you reject...
A sample mean, sam ple size, and sample standard deviation are provided below. Use the one-mean t-test to perform the required hypothesis test at the 10% significance level. X-27, s-4, n-24, Ho : ?-29, Ha : ? 29 EEB Click here to view a partial table of values of to The test statistic is t- Round to two decimal places as needed.)