A metal object at 38.0°C is heated by gaining 11.5 kJ of heat from the environment....

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Question

Answer 1

Answer #1

- q = heat capacity X change in temperature 9 = 1.55 kJ/°C X (Tf -38°C) 11.5kJ = 1.55 kJ/°c x (Tf -38°) Tf - 38°C = 11.5 kJ -

Answer 2

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