2) Calculate the depth in sea water where the pressure is 10 atm.

Question

Question

Answer 1

Answer #1

2) answer) here we have

Ptotal=Po+ $\rho$ gh

Po=atmospheric pressure=1.013*10⁵Pa

Ptotal=10*1.013*10⁵pa

density of seawater=1030kg/m³

10*1.013*10⁵pa=1.013*10⁵pa+1030*9.8*h

9.117*10⁵pa=10094*h

h=911700/10094=90.3 m

so the answer is 90.3 m

Answer 2

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