Question

The sperm whale can dive to a depth of 2250 meters. For sea water with a density of 1020 kg/m3 what is the difference in pressure at this depth as compared to the surface? Supply your answer in atmospheres" (atm), where 1 atm approximately equals 1x105 Pa. (This is an incredibly large pressure. Human bodies would be crushed. The deepest human dive recorded was around 300 m, and even then, the diver had to spend 12 hours to surface from this depth to prevent harm related to the pressure differences at depth. Whales are amazing!) DQuestion 5 1 pts Let us assume that a seal's lungs makes up 10% of its bodies volume when full, and that the average density of a seal is 980 kg/m3 when its lungs are full. If the air in the seal's lungs obeys Boyle's law, at what depth would this seal achieve neutral buoyancy in sea water, which has a density of 1020 kg/m3? Assume there are no changes to other tissues in the seal as it dives and that atmospheric pressure is about 1x105 Pa. Before diving, seals may exhale to reduce the amount of air in their lungs. This would increase their density (decreasing their overall volume), and, therefore, reduce their buoyancy so that it is easier for them to dive.] 6.5 m 16.5 m 165 m 1.65 m

Answer 1

ONE QUESTION AT A TIME PLEASE.

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Pressure at given depth is given as

P = rho * g * h

if the container or water body is open to atmosphere, then total pressure will be

P = atmospheric pressure + pressure at given depth

P = 1 atm + 1020 * 9.8 * 2250

P =   1 atm + 224.91 atm

P = 224.91 atm

as compared to surface, difference in pressure is 224.91 atm