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A bullet is shot straight in the air with an initial velocity of 139 ft/sec. Calculate how high (absolute value in ft) it will go up before it stops and reverses its motion. Assume g resistance is negligible. tion 5 1 pts A heavy object with negligible buoyancy enters water at a speed of 10 m/sec. Assuming a constant deceleration rate of -3.6 m/s2 in water, calculate how deep does it travel below the surface (absolute value of depth) before its speed is reduced to 7.0m/s 2
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Answer #1

Question 3, using third equation of motion,

v​​​​​​2​​​​​ = u​​​​2 + 2as

= 139 ft/sec , than f nad height Rached V) (Ang t (0), (139), 2(-32. 2H4) 2 19 32 lft h- 19.321. ftxSc = 300.02 う6y.yft xh secmi-t heav clohm ward ll = 10 a -3.6 final speed. 1)- = 7.0 wYs 2 드 구.1 m

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