1. Consider a 0.475 M NaA(aq) solution in which HA(aq) has a Ka of 1.950E-03 at...
CHE 152 Acid-base 129 Name Write the appropriate equilibrium reaction for each problem. Use the quadratic equation if the 5% rule does not apply. Show all work for credit. 1. Consider a 0.725 M NaAlag) solution in which HAlag) has a Ka of 2.050E-03 at 25°C. a. Identify the major species present in the NaAlag) solution Major species: b. Calculate the Kb of the conjugate base, A (aq). c. Calculate the pH of a 0.725 M NaAlaq) solution. pH =
1. A solution is prepared by mixing 102.0mL of 0.305M HA with 110.0mL of.285M NaA. The Ka of HA is 0.00000540. B a. Identify the major species: HAMA A b. Calculate the pH of the solution at 298K. pH = c. Calculate the pH of the solution when 20.0mL of 0.10M NaOH is added to the original solution at 298K. pH =
Consider weak monoprotic acid HA(aq) D H+(aq) + A–(aq) with Ka = 4.0 x 10–5 and pKa = 4.40. A solution is composed of 900.0 mL of 0.090 M HA and 0.080 M NaA (10 points). (a) Calculate the pH of this solution. (b) Calculate the pH of the above solution following the addition of 10.00 mL of 2.0 M NaOH (a strong base).
1.A 1.76 M solution of a weak acid HA is found to have a pH of 2.22 Determine Kg of the acid Determine Kb of its conjugate base, A Determine [OH'] in a 2.00 M solution of the weak acid's sodium salt, NaA M Determine the pH of a 2.00 M solution of the sodium salt, NaA 2.The pH of a 1.93 M solution of a weak base B is measured to be 10.82 Determine Kp of the base Determine...
A 0.240 M solution of the salt NaA has pH = 8.40. Calculate Ka for the acid HA.
1. A 2.03 M solution of a weak acid HA is found to have a pH of 2.10. Determine K, of the acid Determine Kb of its conjugate base, A Determine (OH') in a 2.00 M solution of the weak acid's sodium salt, NaA M Determine the pH of a 2.00 M solution of the sodium salt, NaA
A 0.25 M solution of a salt NaA has pH=8.93. What is the value of Ka for the parent acid HA?
show all work Consider that 20.0 mL of 0.10 M HA (an arbitrary weak acid, Ka= 2.5 × 10−6) is titrated with 0.10 M NaOH solution. The ionization of HA in water occurs as the following. HA (aq) + H2O(l) ⇌ A (aq) + H3O (aq) The neutralization reaction between HA and NaOH can be expresses as the following. HA (aq) + NaOH (aq) NaA (aq) + H2O (l) Answer the following questions. A) What will be the initial...
An acid HA has a Ka of 10-7. The pH of a 0.1 M solution of its conjugate base is: options: 7 5 10 13
H aq H g anode An electrochemical cell consists of a H aq 1 .00 M H g) cat ode connected to a which e H concentration a ofa u er cons nu of a weak acid HA(0.116 M), mixed with its conjugate base, A (0.143 M). The measured cell voltage is E°ell 0.163 V at 25 °C, with PH2-1.00 atm at both electrodes. Calculate the pH in the buffer solution and the K of the weak acid. Ka H...