Question

The resistivity of blood is related to its hematocrit, the volume fraction of red blood cells in the blood. A commonly used equation relating the hematocrit h to the blood resistivity ρ(in Ω⋅m) is ρ=1.32/(1−h)−0.79. In one experiment, blood filled a graduated cylinder with an inner diameter of 0.90 cm. The resistance of the blood between the 1.0 cmand 2.0 cm marks of the cylinder was measured to be 258 Ω.

ReviewI Constants Periodic Table Part A The resistivity of blood is related to its hematocrit, the volume fraction of red blood cells in the blood. A commonly used equation relating the hematocrit h to the blood resistivity p in S2 - m) is p 1.32/(1- h) - 0.79 In one experiment, blood filled a graduated cylinder with an inner diameter of 0.90 cm. The resistance of the blood between the 1.0 cm and 2.0 cm marks of the cylinder was measured to be 258 2 What was the hematocrit for this blood? 0.83673 SubmitP Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining

Answer 1

Part A rightarrow Area at cross section of blood in cylinder = A = pi r^2 = 3.14 times (0.90/2 times 106 - 2)^2 = 3.14 times 20.25 times 10^- 6 = 63.585 times 10^- 6 m^2 length of blood in cylinder = 1.0cm = 10^- 2m so R = rho l/A = [1.32/(1 - h) - 0.79] times 1.0 times 10^- 2/63.585 times 10^- 6 OR 258 = [(1.32/1 - h) - 0.79] times 157.2698 OR 258 = 207.5961/1 - h - 124.2431 implies 207.5961/1 - h = 382.2431 implies 1 - h = 207.5961/382.2431 = 0.5431 implies h = 1 - 0.5431 = 0.4569 h = 0.4569