We are given the acceleration and we have find the expression for position, so we use the fact that that acceleration is differentiation of velocity and integrate it to find velocity and we use the fact that velocity is differentiation of position and integrate it to find position as shown below,
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Constants A small object moves along the a-axis with acceleration a(t)(0.0320 m/s3) (15.0 s - t)....
Constants Part A A small object moves along the z-axis with acceleration ar(t) (0.0320 m/s) (15.0 s t). Att 0 the object is at velocity vo -5.50 m/s. -14.0 m and has What is the z-coordinate of the object whent 10.0 s? Express your answer with the appropriate units. Value Units Submit Request Answen
Constants A small object moves along the c-axis with acceleration az(t) = -(0.0320 m/s)(15.0 s – t). At t = 0 the object is at x = -14.0 m and has velocity voz = 8.70 m/s. Part A What is the x-coordinate of the object when t = 10.0 s? Express your answer with the appropriate units. μΑ ? x = 68.3333 m Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Provide Feedback Next >
Item 4 Constants Part A A small object moves along the z-axis with acceleration ar (t)(0.0320 m/s3) (15.0 s - t). At t 0 the object is at -14.0 m and has velocity ox -8.50 m/s. What is the x-coordinate of the object when t 10.0 s? Express your answer with the appropriate units. LA |z= 1 Value Units Submit Request Answer
A small object moves along the x-axis with acceleration Constants Part A A small object moves along the z-axis with acceleration ar(t)-(0.0320 m/s) (15.0 s t). Att 0 the object is at14.0 m and has velocity v0 6.70 m/s. What is the r-coordinate of the object when t 10.0 s? Express your answer with the appropriate units IA 13.33 Im Submit Pra Previous Answers Request Answer X Incorrect; Try Again; 6 attempts remaining Provide Feedback
A small object moves along the x-axis with acceleration ax(t) = −(0.0320m/s3)(15.0s−t). At t = 0 the object is at x = -14.0 m and has velocity v0x = 5.90 m/s. What is the x-coordinate of the object when t = 10.0 s?
a small object moves along the x-axis with acceleration ax(t) =-(0.0320m/s3)(15.0s-t). at t=0 the object is at x=-14.0m and has velocity v0x =4.50 m/s. what is the x-coordinate of the object when t=10.0s?
A small object moves along the x-axis with acceleration ax(t) = −(0.0320m/s3)(15.0s−t). At t = 0 the object is at x = -14.0 m and has velocity = 5.20 m/s. What is the x-coordinate of the object when t = 10.0 s?
An object moves in along the x-axis with an acceleration given by: a = 4t (m/s2). The position of the object at t=0.0 is 7 m, and its velocity at t=0.0 s is 5 m/s. Calculate the position at t=6 s.
An object traveling along the x-axis wit h constant acceleration has velocity v = +13.0 m/s when it is at x-6.0 m and v-+ 15.0 m/s when it is at x-10.0 m, what is its acceleration? t is at x 10.0 m. What is its acceleration? m/s
An object moves along the y axis according to the equation y(t) = b + ct3, where b = 7.50 m, c = 3.50 m/s3, and y(t) will be in meters when t is entered in seconds. Determine the following. (a) average velocity of the object during the time interval t = 1.00 s to t = 3.00 s m/s (b) instantaneous velocity at the time t = 2.00 s m/s (c) acceleration of the object at the time t...