Question

Constants A small object moves along the a-axis with acceleration a(t)(0.0320 m/s3) (15.0 s - t). At t 0 the object is at a 14.0 m and has velocity 8.10 m/s

nts Part A What is the x-coordinate of the object when t = 10.0 s? Express your answer with the appropriate units. /s aue Units Submit Request Answer Provide Feedback

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Answer #1

We are given the acceleration and we have find the expression for position, so we use the fact that that acceleration is differentiation of velocity and integrate it to find velocity and we use the fact that velocity is differentiation of position and integrate it to find position as shown below,

dt dvx - 2 2 0032)1St- t2 or at t-0, x- -14m, Put thio above to -0032(3522-4 〉 put t- LOs and we getx - 48.3***************************************************************************************************
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