Question

7. Balance the following reaction equation and then do the calculations. Show your work below. 2 ch,0H + 30- 4.10 + 2 coz a. How many grams of Co, are produced from the combustion of 10.0 grams of CH,OH? b. How many grams of H20 are produced from the combustion of 20.0 g of CH,OH? c. How many grams of O, are needed to react with 50.0 grams of CH.OH? d. How many grams of CH,OH are needed to produce 40.0 grams of H2O?

Answer 1

the balanced equation is as follows

2 CH3OH + 3 O2 ----------------> 2 CO2 + 4 H2O

no of moles = mass / molar mass

a) for CH3OH = 10g / 32.04 g/mol => 0.3121 moles

2 mol CH3OH --------------------> 2 mol CO2

0.3121 mol ------------------------>?

=> 0.3121 * 2 / 2 => 0.3121 mol

mass of CO2 = 0.3121 * 44 => 13.733 grams

b) for CH3OH = 20g / 32.04 g/mol => 0.6232 moles

2 mol CH3OH --------------------> 4 mol H2O

0.6242 mol ------------------------>?

=> 0.6242 * 4 / 2 => 1.2484 mol

mass of H2O => 1.2484 * 18 => 22.472 grams

c) for CH3OH = 50g / 32.04 g/mol => 1.5605 moles

2 mol CH3OH --------------------> 3 mol O2

1.5605 mol ------------------------>?

=> 1.5605 * 3 / 2 => 2.341 mol

mass of O2 = 2.341 * 32 => 74.91 grams

d) moles of H2O = 40 / 18 => 2.222 moles

2mol CH3OH ---------------> 4 mol H2O

? -------------------------> 2.222 mol

=> 2.222 * 2 / 4 => 1.111 moles

mass of CH3OH => 1.111 * 32.04 => 35.6 grams