Question

How many grams of nitric acid, HNO₃, are required to neutralize (i.e. completely react with) 3.33 moles of Ca(OH)₂ according to the balanced chemical reaction:

2HNO₃ + Ca(OH)₂ --> 2H₂O + Ca(NO₃)₂

Answer 1

Molar Mass of HNO3 1 008 14 0o67 t 3 C16 63 0l4 m/mol MM H NO3 moles of Ca cOH )2 ncal OH)2 3.33 moles 2H20CaCNO3)2 CaloH) 2 HN03 HNO om CaCOH2 amalysis on mole-mole HNO3 na(0)2 2 2x 3.33 moles EaNHu 66 moles xMHHN03 nHNO3 HNO3 wedht of HND w (6.66 x 63 047) m 4 19- (8m WHNO3

Answer 2

According to the Balanced equation:

1 mole Ca(OH)2 require 2 mole HNO3

3.33 mole Ca(OH)2 require 2×3.33 mole

= 6.66 mole HNO3

1 mole HNO3 = 63 g

6.66 mole HNO3 = 63×6.66 g

= 419.58 g HNO3

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