Question

How many moles of Al are necessary to form 23.6 g of AIBr; from this reaction: 2 Al(s) + 3 Brz(1) ► 2 AlBrz?
How many grams of nitric acid, HNO3, are required to neutralize (completely react with) 4.30 g of Ca(OH)2 according to the ac
0 0
Add a comment Improve this question Transcribed image text
Answer #1

molesd Alerz = mass molan mass = 22:6 = 0.088 mol 266.69 Al + 3br, —> 241 Bry mole of Al need = tx mile of Al Brz - 4X0.086 =

Add a comment
Know the answer?
Add Answer to:
How many moles of Al are necessary to form 23.6 g of AIBr; from this reaction:...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT