Question

Warmup 5 Dr. Colbert two dim motion Phy Spring2019 Due Jan. 25 Name: 1. Spiderman releases his webbing and launches into the air moving at 50.0m/s at an angle of 40° above the horizontal. He is trying to clear a wall that is 100 m ahead of him and a height of 60.0m a. What are the horizontal and vertical components of velocity? wall? By how much doses Spidceman (h)n the wal d. What is the velocity vector of Spiderman as he passes (or hits) the wall? (magnitude and direction).

Answer 1

Horizontal component of velocity = v_x = v cos 40 degrees = 38.302 m/s Vertical component of velocity = v_y = v sin 40 degrees = 32.14 m/s time taken by Spidey to reach wall t = 100/v cos 40 degrees = 2.61083 sec height of Spidey = v_y t - 1/2 g t^2 = 50.5115 m Spidey will hit the wall and will not be able to cross it and misses it by 9.49 m Horizontal component of velocity when spidey hits the wall = 38.302 m/s Vertical component = 32.14 - (9.8) (2.61083) = 6.5539 m/s Velocity = 38.86 m/s at 9.71 degrees with horizontal

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