Question

Group 4 - Titration Data Titration with 10 ml of 0.1 N oxalic acid, used 12.5 mL NAOH solution. Please calculate the concentration of these solutions and post the details of your calculations and final results so I can check them. Titration Data was measured with a 50 mL burette with graduations of 0.1 mL. All other reagents were measured with a 5 mL pipette with graduations of 0.1 mL. Your reagents are labeled Group 4

Answer 1

The 5 mL pipette was used 2 times two pour the complete 10 mL of 0.1 N oxalic acid solution .

NaOH was taken in a burette and at 12.5 mL , it was done to end point .

Strength of Oxalic Acid = 0.1 N

Strength of NaOH to be found out .

From the Standard formula of Volummetry ,

$\dpi{120} \bg_white S_{NaOH}\times V_{NaOH}= S_{Oxalic}\times V_{Oxalic}$

$\dpi{120} \bg_white \therefore S_{NaOH} = \frac{S_{Oxalic}\times V_{Oxalic}}{V_{NaOH}}$

$\dpi{120} \bg_white \therefore S_{NaOH} = \frac{0.1\: N\times 10 \: mL}{12.5\: mL}= 0.08\: N$

Thus , strength of NaOH is 0.08 N . [ANSWER]