Question

I’m so confused on how to do any of this.

Name Date General Chemistry I Lab CHE 1211 Data: Concentration of NaOH Trial Titration (to be used as practice) Initial burete eading4.0 ml Final burette reading 20.h m 22.om. Volume of NaOH used Repeat until 2 successful titrations are achieved. Titrations (to be used in calculations) K.Oml 0.bml 35.o mL 22.3 mL 38.5ml ↓ 30.6 mL45.0 mL 49.0 mL 35.5mL50.0 me 22.0mL H. m0 ml 1b.20 m 4.5ml Initial burette reading Final burette reading Volume of NaOH used Calculations 1. Complete and balance the equation. NaMm) + HClio-Netta6pltH00 2. Using the molarity formula, calculate the moles of NaOH used in each successful titration sample Sample 1 Sample 2 3. Using the balanced equation, determine the moles of HCahO, in each successful titration sample. Sample 1 Sample 2 46 Name Date General Chemistry I Lab CHE 1211 Calculate the molarity of the vinegar for each successful titration sample. 4. Sample I Sample 2 S. Calculate the average molarity for the samples. Post Lab Questions 1. Most vinegar claim to be 5% (or higher) acetic acid by mass (g of acetic acid/ g of vinegar. Use Hint: Use the volume of vinegar and the density to find the mass; Density of vinegar is 1.OI gml results to calculate the % acetic acid by mass for vinegar analyzed. int r de h ely of wneger is 1,01gm Sample I Sample 2 Average Mass % was the manufacturer correct (the vinegar was 5% acetic acid or higher)? Calculate the molarity of the HCL. 2. A 10.0 mL sample of HCI requires 22.3 mL. of 0.330 M NaOH to reach the endpoint in a titration. 47

Answer 1

Hii. You have not mentioned how much ml of vinegar sample you have taken for the titration. Let's say 10ml you have to change with your volume.

Sample	S 1	S2	S3	S4	S5
Volume of NaOH used (mL)	16.6	14.4	14.0	16.2	14.5
Moles of NaOH (mmoles)	8.3	7.2	7.0	8.1	7.25
Moles of vinegar (mmoles)	8.3	7.2	7.0	8.1	7.25
Molarity of vinegar M	0.83	0.72	0.7	0.81	0.725
Average molarity (M)	0.757

Molarity of vinegar

= moles of vinegar / volume of vinegar used