Question

In a firm with 500 employees, the CEO is interested in knowing what level of commitment the company’s employees has in the firm. The CEO suspects that approximately 250 full-time employees are more committed (e.g., emotional attachment to the firm) than the nearly 250 contracted personnel. The CEO asked the human resources director to survey all employees using an established measurement scale that taps into organizational commitment. The dataset represents the average scores of each worker on this scale. Test the null hypothesis that there is not a statistically significant difference between the two groups of workers using the independent samples t-test in both Excel and SPSS.

In your write-up of this study, please briefly describe the purpose of the study, describe the use of the t-test to explore this hypothesis, and report the findings in detail. Last, please explain the results in narrative form. In other words, tell the story of the study beyond simply calculating the t-value.

Length: 3-5 pages

Job Status Commitment 5 | 4 5 | 5 3.5 || 25 3.25 0 | 4.5 3 2.5. 4 25 3.25 4.25 3.5 375 5 4.5. 4 | 2.5 4 25 25 4 25 ઠાના નાગનારા- વારા રાની રાગ-1ના રાજારાના નાના ગાવાની નાજારાવાના નાના નાના નાના 5 | 4 | 4.25 4.5. 2.5 3 4 2.5 2.5 ૩. 25 45 | 4 | 5 1 1 | 3.25 4

Answer 1

Hypothesis:

Null hypothesis: H0:$\mu 1=\mu 2$

Alternative hypothesis: H1:$\mu 1\neq \mu 2$

Using SPSS software hypothesis testing is:

here significance value is 0.449>0.05 so we accept H0 so there is no statistically significant difference between the two groups.

T-Test [DataSeto] Group Statistics commitment job status grp 1 grp 2 N N Mean Std. Deviation 3.675 .8334 30 3.7588107 Std. Error Mean .1522 .1480 Independent Samples Test Levene's Test for Equality of Variances t-test for Equality of Means Sig. df 58 Sig. (2-tailed) .696 Mean Difference -.0833 Std. Error Difference 2123 95% Confidence Interval of the Difference Lower Upper --5083 .3416 582 .449 -393 commitment Equal variances assumed Equal variances not assumed - 393 57.956 .696 -0833 2123 --5083 .3416

Using MS-excel:

F-Test Two-Sample for Variances
	Variable 1	Variable 2
Mean	3.675	3.758333
Variance	0.694612	0.657256
Observations	30	30
df	29	29
F	1.056837
P(F<=f) one-tail	0.441345
F Critical one-tail	1.860811

here also 0.441345>0.05 so we accept H0 so there is no difference

conclusion:

Here we accept H0 so there is no difference between two groups they have equal means

About independent t-test:

1) The two-sample t-test is used to compare two means of two independent populations denoted by$\mu 1 and \mu 2$

2) samples of n1 and n2 observations are randomly selected from the two populations

3) The greater the difference between sample means the greater the evidence against the hypothesis of equality of populations means are untrue.