A.
Express F1 as a Cartesian vector.
B. Express F2 as a Cartesian vector.
C. Express F3 as a Cartesian vector.
(A) F1 = (15*sin40 i + 15*cos40 j) kN = (9.64 i + 11.50 j) kN
(B) and (C) solutions are in solved in sheet.
A. Express F1 as a Cartesian vector. B. Express F2 as a Cartesian vector. C. Express...
(Part b) Write the vector sum F1+F2 +F3 in terms of the unit vectors i and j. Use Fi = Fi), F, = |F2), and F3 = |F3| to be the magnitude of the vectors Fi, F2, and F3, respectively. Drag the appropriate terms to construct the correct expression. Pay attention to the difference between a and in the trigonometric functions. Ē + F2 + Fz (F1 + F2 + F3 + + F2 + F3 · α E +X...
Determine the magnitudes of F1, F2, and F3 for equilibrium of the particle. The applied forces and Q are applied at point O. Given P = 2.8 + xx (kN) and Q = 8.5 + xx (kN), where xx is the last two digits of your student ID number. If your student ID is 6x-XXXXXX-xxx1-2, P = 2.8 + 12 = 14.8 kN and Q = 8.5 + 12 = 20.5 kN. F2 30° 25 15 P 1.1 Force Q...
The belt passing over the pulley is subjected to forces
F1 and F2, each having a
magnitude of 40 N. F1 acts in the
−k direction. Set θ=0∘ so that
F2 acts in the −j
direction.
(Figure 1)
Determine the equivalent force. Express the result in Cartesian
vector form.
r80 mm 300 mm
Vector subtraction F1 - F2 can be considered as a special
vector addition, namely, F1 - F2 = F1 + (-F2). Suppose that the
cases of vector addition 1 and 2 in this experiment were vector
subtraction F1 - F2. In which quadrant would the resultant vector
be in each case?
3. Vector subtraction can be considered as a special vector addition, namely, -R = A + (-A) . Suppose that the cases of vector addition 1 and 2 in...
There are two unitless vectors: F1-8.92 i + 17.37; F2 - 12.44 i+7.11j A third vector is added to them such that they add up to to the null vector: Fq+F2+F3 - 0 What is the angle of the third vector with respect to the +x-axis? Answer in degrees, and to the fourth decimal place. Question 9 There are two unitless vectors: Fq - 8.92 i + 17.37) F2 - 8.311 - 10.971 A third vector is added to them...
The functions are: f1(a,b,c,d) = ∑m(0,1,3,6,9,11) , f2(a,b,c,d) = Πm(2,3,4,5,7,10,11,12,13,14,15) and f3(a,b,c,d) = ab’c’ + a’b’c +b’cd Complete the following problems for functions f1, f2, and f3 1. Implement the 3 functions on one(1) 4x16 decoder
Find the forces (F1,F2,F3 lb) in Fig. 364.
(A=26, B=34, C=77) deg,
(D=3, E=5, F=6) ft,
F4=3740 lb
Find the forces (F1,F2,F3 lb) in Fig. 364. (A=26, B=34, C=77) deg, (D=3, E=5, F=6) ft, F4=3740 lb
Problem 1 Write the output functions of the PLA circuit given at the left. a. F1 b. F2 c. F3
Problem 1 Write the output functions of the PLA circuit given at the left. a. F1 b. F2 c. F3
Fi 60 135 60° 609/ 30 (4 m, 4m,-2m) If F1- 8.26 KN, F2 3B4 KN, and F3 12.2 KN, determine the magnitude and direction of F required for equilibrium. F1 is rotated 30 degrees in the x-y plane and 60 degrees up in the z direction. Alpha, Beta, and gamma for F2 are 135, 60 and 60 degrees, respectively. F3 passes through the origin and another point (4,4,-2).
Chapter 12, Problem 015 Forces F1 F2, and F3 act on the structure of the figure, shown in an overhead view. We wish to put the structure in equilibrium by applying a fourth force, at a point such as P. The fourth force has vector components F h and F v . We are given that a= 0.755 m, b 3.85 m, c = o.535 m, F1 = 11.6 N, F2 = 13.3 N, and F3 = 2.43 N. Find...