Question

A hydrocarbon gas has a density of 1.18 g/L at 20.°C and 1.00 atm. An analysis gives 85.7% C and 14.3% H. What is the molecular formula?

Answer 1

density (d) = 1,18 g/L Temperature (T) = 20°C = 20 + 273k = 293k pressure (P)= I atm. So from ideal gas d = pm m (molecular mees) = RT = 1.18X0.0821 X 293 g/mol m = 28.38 olmal carbon (c) 85.7 85.7 Hydrogen (4) 14.3 14.3 in gm. mole 85.7 12 7.14166 14.3 Simplest Ratio 7.14166 Tol4166 14.3 Y-14166 so empirical formala = C,H2 empirical formula mess = 14 g/mol Molecular formule mees empirical formula mass 28.33 14 juma

Molecular formula = (empirical formalan = (CH2), санч