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Which chemical reaction represents the loss of the THIRD proton from citric acid (H3C6H307) H2C6H50; (aq) + H20(1) -- H3C6H30
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Answer #1

After loosing 2 protons, the compound would be HC6H5O72-

This will loose 3rd proton and form C6H5O73-

So, the reaction should be:

HC6H5O72-(aq) + H2O(l) -> C6H5O73-(aq) + H3O+(aq)

Answer: option 2

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