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Study the balanced equation. 3Hg(OH)2 + 2H3PO4 → Hg3(PO4)2 + 6H20 How many mol of phosphoric acid (H3PO4) reacted to form 3.1

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Answer #1

Equation : 3Hg(OH), +2H3PO4 — Hg3(PO4)2 + 6H,0 No of moles H,0 formed = 3.13x10^mol H,0 Volume of HyPO, reacted = 3.13x10 mo

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