Question

Interactive Exercises 6.01: Static Frictional Force Suppose you work for an engineering firm, and your task is to study the frictional force between aluminum and a certain alloy of steel that your firm wishes to use in some major construction projects. As part of this study, you place an aluminum block of mass 1.00 kg on a flat plate of the steel alloy, as shown in the simulation. Using the slider at the top of the animation, you can specify the magnitude of a force Fapp applied to the aluminum block. This force acts in the +x direction. Simulation The Static Frictional Force Question 1 Your answer is partially correct. Try again. Select an applied force magnitude of 2.5 N. Observe that the block remains in equilibrium-with an acceleration of zero. The force on the block that balances the applied force is called the static frictional force. We shall use the label f , to denote the static frictional force. Mouse over the arrows in the simulation to see the labels on all four force vectors. What is the static frictional force? Enter a numerical value in the blue box (first box) and a unit vector in the red box (second box) -d-2.5 N) Edit the tolerance is +/-2% By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor.

Part b) Increase the applied force magnitude to the largest value permitted by the simulation.

The words “Block on verge of slipping” should appear. This means that the static frictional force on the aluminum block has reached its physical upper limit. It is not possible, given the intermolecular forces between the atoms in the welds, for the static frictional force to be any larger. We shall label this maximum static frictional force as f→s,max. What is f→s,max on the block in unit-vector notation? Enter a numerical value in the blue box (first box) and a unit vector in the red box (second box).

f→s,max=

(Did you set the applied force to its largest possible value? Is the mass of the block set to 1.0 kg? N)

· Did you remember to specify the direction of the maximum static frictional force?Edit

the tolerance is +/-2%

Answer both part must

Answer 1

In the part (a), you should write i instead of - i, as you have already used negative sign in your magnitude of fs vector (the first box), so using '- ' sign with i again made fs positive.

In part (b), the magnitude of f->s, max will be negative of the magnitude of maximum applied force (should write in the first blue box) and in second red box, you should write i. As your simulation can not be accesed and you have not written the numerical value of maximum applied force, so I could not write the numerical value of

f-> s, max.