Question

Review Part A An object with a change of -21 C and a mass of 4710-2 kg experiences an upward electric force, due to a unform eleclric Seld equal in magnitude to ts weght Find the magntude of the electric feld Express your answer using two significant figures N/C Submit Part 8 Find the direcion of the electric feld e upward downward Submit ▼PartC If the electric charge on the object is doubled whle ts mass remains the same, find the drection and magnitude of ts acceleration Express your answer using three significant figures /s Submit Part D f the electric charge on the object is doubled while its mass remans ind the deection and magntude of its acceleration O upward to the let to the rght

Answer 1

(NOTE: From the figure it is not clear whether the charge is positive or negative. Anyway I have considered it to be negative. If in case it is positive then just reverse the direction of field to that mentioned in the following answer.)

Summary: Force on a charge due to electric field is given by F = qE,

Here, F=force due to the field E

q= magnitude of charge

Summary: Force on a charge due to electric field is given by F = qE, Here, F = force due to the field E q = magnitude of charge charge on the object = -2.1 mu C most of the object = 4.7 times 10^-2 Kg From the figure The force due to electric field is in upward direction The weight of the body acts in the downward direction. According to given situation: The two forces acting on the body are and opposite. Force on a charge 'q' due to electric field E^vector is given by: F^vector = q E^vector here q is negative. (considering upward direction in the figure to be positive the F^vector points in positive (upward) direction. So to balance the mass of the object the E^vector (electric field) should point in downward direction because here the object is negatively charged. \r\n so, to balance the object: Force due to E^vector = Force due to gravity implies F^vector_field = F^vector_mass
{NOTE:- for part C, the same calculation can be done by first calculating the net force on the object i.e. F_NET = F_Field - F_Mass

_{and then the acceleration can be calculated by dividing the mass of the object from this force.}}

_{{NOTE: As I mentioned earlier, I have taken the charge to be negative here (since the image is not so clear) , so if the charge is positive then the direction of field in this case would be along positive Y-axis or upward direction}}

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