The index of refraction for plastic can be caulated by both Snell's law:
n1 sin(theta1) = n2 sin(theta2)
and the critical angle
n1 sin(theta90) = n2 sin(theta-c)
Out of these two, critical angle method is more effective as We already know that at air interface the angle is 90 deg and n = 1.
for the known value if cirtical angle,
n(plastic) = sin90/sin(theta-c)
Which method ( snell’s law or critical angle) is more effective for measuring the index of...
You can determine the index of refraction of a substance by measuring its critical angle for total internal reflection. Randomized VariablesΘc,w = 63.8° a) What is the index of refraction of a substance that has a critical angle of 63.8° when submerged in water (with index of refraction 1.333)? b) What would the critical angle be for this substance in air?
Snell’s law can tell the refracting angle if we know a. The index of refraction for the medium Light rays enter b. The index of refraction for the medium Light rays emerge c. The angle of incidence d. All of the above
Problem 4: You can determine the index of refraction of a substance by measuring its critical angle for total internal reflection. Randomized Variables: Θc,w = 65.2° Part (a) What is the index of refraction of a substance that has a critical angle of 65.2° when submerged in water (with index of refraction 1.333)? Numeric : A numeric value is expected and not an expression. n1 = __________________________________________ Part (b) What would the critical angle be for this substance in air? Numeric : A numeric...
Problem 4: You can determine the index of refraction of a substance by measuring its critical angle for total internal reflection. Randomized Variables: Θc,w = 65.2° Part (a) What is the index of refraction of a substance that has a critical angle of 65.2° when submerged in water (with index of refraction 1.333)? Numeric : A numeric value is expected and not an expression. n1 = __________________________________________ Part (b) What would the critical angle be for this substance in air? Numeric : A numeric...
The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 40.3° what is the index of refraction of the material? Tries 0/20 A light ray strikes this material (from air) at an angle of 34.7° with respect to the normal of the surface. Calculate the angle of the reflected ray (in degrees). Tries 0/20 Calculate the angle of the refracted ray (in degrees). Tries 0/20 Assume now...
The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If theta_c = 40.5 degree what is the index of refraction of the material? Tries 0/12 A light ray strikes this material (from air) at an angle of 36.0 degree with respect to the normal of the surface. Calculate the angle of the reflected ray (in degrees). Tries 0/12 Calculate the angle of the refracted ray (in degrees). Tries...
Evaluate the angle of incidence or refraction using Snell's law or the critical angle sin = n/ny The unknown quantity to be determined in part (c) is the critical angle for the glass/air boundary. The critical angle is given by the following. sin - 12 for ng > 2 ni In this problem, n, = 1.63, the index of refraction of the glass, and n, - 1.00, the index of refraction of air What is the critical angle for the...
The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If Oc= 40.4º what is the index of refraction of the material? 1.54 You are correct. Previous Tries A light ray strikes this material (from air) at an angle of 37.2° with respect to the normal of the surface. Calculate the angle of the reflected ray (in degrees). 23.07 Submit Answer Incorrect. Tries 3/20 Previous Tries Calculate the angle...
What is the index of refraction of a substance that has a critical angle of 61.0° when submerged in ethanol, which has an index of refraction of 1.361?
You can determine the index of refraction of a substance by determining its critical angle. (a) What is the index of refraction of a substance that has a critical angle of 620 when submerged in water (nwater = 1.333)? Your answer should be a number with three decimal places, do not include the unit.