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Suppose that the average person watches 6.25 hours of television per day with a standard deviation...

Suppose that the average person watches 6.25 hours of television per day with a standard deviation of 2.75 hours. Assuming television viewing is normally distributed, what percentage of people watch over 10 hours of television per day?

math   Statistics-And-Probability   
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Answer #1

Given that, mean()- 6.25 hods standard deviation (σ): 2-75 hours P(X >10) = P/X-ll P(32 1,36) |-o-9131 10-6-25 2-f5 > = :) p(X > 10) = 0.0869 percentage : 0.0867*100 rn Therefore 8.69% 아-People-loatch over lo hours o television per day 8-69% 2. -

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