Question

Suppose a study reported that the average person watched 5.39 hours of television per day. A random sample of 15 people gave the number of hours of television watched per day shown. At the 11​% significance​ level, do the data provide sufficient evidence to conclude that the amount of television watched per day last year by the average person differed from the value reported in the​ study? (Note: x overbarxequals=3.933 hours and sequals=1.645 ​hours.)

1.9 6.3 2.0 4.1 3.4 5.6 2.0 5.0 6.0 4.6 4.1 6.2 3.1 3.0 1.7

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Click here to view a partial table of values of

t Subscript alphatα.

Set up the hypotheses for the​ one-mean t-test.

Upper H 0H0​:

muμ

▼

nothing

Upper H Subscript aHa​:

muμ

▼

nothingThe test statistic is

ttequals=nothing.

​(Round to two decimal places as​ needed.)

Identify the critical​ value(s). Select the correct choice below and fill in the answer box within your choice.

​(Round to three decimal places as​ needed.)

A.The critical

value isvalue is

negative t Subscript alpha Baseline equals−tα=nothing.

B.The critical

values arevalues are

plus or minus t Subscript alpha divided by 2 Baseline equals plus or minus±tα/2=±nothing.

C.The critical

value isvalue is

t Subscript alpha Baseline equalstα=nothing.

the null hypothesis. The data

sufficient evidence to conclude that the amount of television watched by the average person is

the value reported in the study.

Click to select your answer(s).

Answer 1