A)
Molar mass of CO,
mm = 28.01 g/mol
= 0.02801 Kg/mol
T = 296 K
vrms = sqrt (3*R*T/M)
here : T is temperature in Kelvin
and M is molar mass in Kg/mol
So,
vrms = sqrt(3*8.314*296.0/0.02801)
= 5.134*10^2 m/s
Answer: 5.13*10^2 m/s
B)
Molar mass of CO2,
mm = 44.01g/mol
= 0.04401 Kg/mol
T = 296 K
vrms = sqrt (3*R*T/M)
here : T is temperature in Kelvin
and M is molar mass in Kg/mol
So,
vrms = sqrt(3*8.314*296.0/0.04401)
= 4.096*10^2 m/s
Answer: 4.10*10^2 m/s
circle answers Exercise 5.84 Calculate the root mean square velocity and kinetic energy of CO, CO2,...
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PLEASE PLEASE HELP! Calculate the root mean square velocity and kinetic energy of CO, CO2, and SO3 at 298 K Part A. Calculate the root mean square velocity of CO at 298 K . Part B. Calculate the root mean square velocity of CO2 at 298 K . Part C. Calculate the root mean square velocity of SO3 at 298 K . Part D. Calculate the kinetic energy of CO at 298 K . Part E. Calculate the kinetic energy...
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