A sample of C5+ ions is prepared with the electron in the n = 7 state. The system emits a photon with a wavelength of 343.7 nm. Which shell (value of n) does the electron end up in?
Please enter your answer as a numeric integer. For example, if your answer is one, enter 1
wavelength = 343.7 nm
= 3.437*10^-7 m
Here photon will be emitted
1/lambda = R*Z^2* (1/nf^2 - 1/ni^2)
R is Rydberg constant. R = 1.097*10^7
Here Z = 6 for carbon
1/lambda = R*Z^2* (1/nf^2 - 1/ni^2)
1/3.437*10^-7 = - 1.097*10^7* 6^2*(1/nf^2 - 1/7^2)
(1/nf^2 - 1/7^2) = 7.367*10^-3
1/nf^2 = 2.778*10^-2
nf^2 = 36
nf = 6
Answer: 6
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