Question

A neutral hydrogen atom in its normal state behaves like an electric charge distribution that consists of a point charge of magnitude $e$ surrounded by a distribution of negative charge whose density is given by $\rho (r)=-Ce^\frac{-2r}{a_0}$ . Here $a_0=0.53\cdot 10^{-10}$ m is the Bohr radius, and $C$ is a constant with the value required to make the total amount of negative charge exactly $e$. What is the electric field strength for radius $r\geq a_0$? What is the electric field strength at radius $r=\frac{a_0}{2}$ ?

Answer 1