Question

100 J of heat was removed from 50 g of an iron bar at 20 ^oC.  What is the final temperature after the iron bar lost the heat? (The specific heat of iron is 0.5 J/g^oC.)

Answer 1

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q= heat removed = -100.5 negative sign indicate that heat by iron bar i's relerued initial temperature & Ti= 20°c let final temperature is TF change in temperature - OT - Ti-Ti = (T6 - 2000 ) man of iron bave = m = 50 g specific heat of iron = c = 0.5 J 19°C 2= MCAT > - 100 J = 50g x 0.5J/gc x (TA -20°c ) - Tf -20°c = -4°C To = -4°C + 20°C = 16°C Hence, the final temperature after the iron bout lost the heat is 16°C