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how many mmoles of oxalate, C2O4^2- ?
Mass of sample - What was the initial mass of the weighing paper in Trial #1? 0.2000 g Previous Answers ✓ Correct Part B Mass
Titration volume of KMnO4 - What was your initial reading in Trial #1? 0.51 ml Submit Previous Answers ✓ Correct Part E Titra
Calculations - how many mMoles of oxalate, C202 in Trial #1? 1Η ΑΣΦ + + Ο ΕΞ) ? mmol


mmol Na2C204 = 0.20 gx 1 mol 109 mmol - = 1.5 mmol 134.0 g 1 mol The reaction requires 2/5 mmol KMnO4 for each mmol Na C204.
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Answer #1

The reaction needs 2 mmal kM non per mol Oy ions (Na2C2O4). molarity KMnO4 = 0.020 M = 0.020 mmollane Volume of KM non in Tri

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