Question

oruul Uuline. Puuur, Table 2) A student determines the time required for 10% reaction by the method described in part A of the procedure of this experiment. She records a time of 45.6 seconds for trial 1, 40.2 seconds. for trial 2, and 43.4 seconds for trial 3. Rate of a. Calculate the average time (in seconds) required for 10% reaction. X Temperatur b. Calculate the average rate (in M/s) required for 10% reaction. 2) Concentra c. Calculate the rate constant, k, in s').

Answer 1

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O as follow 3 let me reachon be represented A - B at to 100 at tat 90 10 As 10% of the reaction is followed. Time talun in Firt, necond, mird tried is 45.6, 40.2 43.4 Mr. (a) so, average time: 45.6 + 40.2 + 43.4 1 avenage hime = 43.066 sec o average rate = r . dne change in concentration of Reaclunt ato change in time during Roachion. N2 = go Ti=0 ni= 100 T2 =43.066 sec ... rate: -40-100) 43.066-0 Tavg. rate = 0.2322 m/sec/

PANE 2 © rate constanta K acconding to me first orden Reaction; ir= 2.303 log a a-n KD 2:30 ni K: 2.303 90 43.06 K: 2.303 log on to TK = 0.00244728