Question

HW: 2-1-12 Using the parallelogram law, trigonmetrically find the magnitude of the resultant of F, and F2 knowing that F1-250N and F2-175% Use the squares in the figure to determine the directions of the forces. Example, ø- tan1 (rise/run) Answer(s): 2 Force magnitudes are not drawn to scale.

Answer 1

Here i write run as x and rise as y

F_1 vector = 250 times 2/squareroot 2^2 + 4^2 x^^+ 250 times 4/squareroot 2^2 + 4^2 y^^= 500/squareroot 20 x^^+ 100/squareroot 20 y^^F times_2 = -175 times 1/squareroot 1^2 + 3^2 x^^-175 times 3/squareroot 1^1 + 3^2 y^^= -175/squareroot 10 x^^-525/squareroot 10 y^^Parallelogram law states that the vector in same direction added in same direction F vector = F_1 vector + F_2 vector = x^^(500/squareroot 20 - 525/squareroot 10) y^^= 56.46 x^^+ 57.58 y^^Resultant = squareroot (56.46)^2 + (57.58)^2 N = 80.64 N Angle = tan^-1 (57,58/56,46) = 45,56 degree