P = 775 torr = 775 / 760 = 1.02 atm
V = 25.2 L
T = (273 + 25) = 298 K
ideal gas equation,
PV = nRT
or
1.02 atm * 25.2 L = n * 0.0821 L-atm / mole-K * 298 K
or
n = 1.05 mole.
thus
mole of SO2 = 1.05 mole.
4 mole FeS react with 7 mole O2 to form 2 mole Fe2O3 and 4 mole SO2.
grams of FeS = (4 / 4) * 1.05 = 1.05 mole = mole * molar mass = 1.05 mole * 87.91 g/mole = 92.36 g (answer)
лапто 0821 273/sl.44L of 2 6.25.2L of sulfur dioxide gas was collected over water at 25°C...
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