2KClO3(s) -----------> 2KCl(s) + 3O2(g)
2moles of KClO3 to gives 3 moles of O2
2*122.5g of KClO3 to gives 3moles of O2
5.25g of KClO3 to gives = 3*5.25/(2*122.5) = 0.0643 moles of O2
n = 0.0643moles
T = 32+273 = 305K
P = 725/760 = 0.954atm
PV = nRT
V = nRT/P
= 0.0643*0.0821*305/0.954 = 1.687L of O2 >>>>answer
2KClO3(s) -----------> 2KCl(s) + 3O2(g)
2moles of KClO3 to gives 3 moles of O2
2*122.5g of KClO3 to gives 3moles of O2
5.25g of KClO3 to gives = 3*5.25/(2*122.5) = 0.0643 moles of O2
n = 0.0643moles
T = 0+273 = 273K
P = 1atm
PV = nRT
V = nRT/P
= 0.0643*0.0821*273/1 = 1.44L of O2 >>>>answer
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