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CHEM 2A Class Pack F18 Ideal Gas Law and Reactions 15. What volume of oxygen is collected when 5.25g of potassium chlorate is
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Answer #1

2KClO3(s) -----------> 2KCl(s) + 3O2(g)

2moles of KClO3 to gives 3 moles of O2

2*122.5g of KClO3 to gives 3moles of O2

5.25g of KClO3 to gives = 3*5.25/(2*122.5)   = 0.0643 moles of O2

n = 0.0643moles

T   = 32+273   = 305K

P   = 725/760    = 0.954atm

PV = nRT

V   = nRT/P

      = 0.0643*0.0821*305/0.954   = 1.687L of O2 >>>>answer

2KClO3(s) -----------> 2KCl(s) + 3O2(g)

2moles of KClO3 to gives 3 moles of O2

2*122.5g of KClO3 to gives 3moles of O2

5.25g of KClO3 to gives = 3*5.25/(2*122.5)   = 0.0643 moles of O2

n = 0.0643moles

T   = 0+273   = 273K

P   = 1atm

PV = nRT

V   = nRT/P

      = 0.0643*0.0821*273/1 = 1.44L of O2 >>>>answer

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