Pressure of O2 = 747 - 23.8 => 723.2 mm of Hg
= 723.2/760 atm
Temperature= 298 K
Volume = 6.24 L
Using ideal gas equation
PV = nRT
n = 6.24×723.2/760×0.0821×298
=> 0.243 mol
Mass =0.243×32 => 7.77 g
2) pressure of O2 = 751-23.8 => 727.2 mm of Hg
PV = nRT
n = 9.09×727.2/760×0.0821×298
= 0.359 mol
Moles of KClO3 reacts = 2×0.359/3
=> 0.239 mol
Use the References to access important values if needed for this question. Oxygen gas can be prepared by heating p...
Use the References to access important values if needed for this question. Oxygen gas can be prepared by heating potassium chlorate according to the following equation: 2KCIO3(s)—>2KCl(s) + 302(g) The product gas, O2, is collected over water at a temperature of 25 °C and a pressure of 749 mm Hg. If the wet O2 gas formed occupies a volume of 8.32 L, the number of grams of O2 formed is g. The vapor pressure of water is 23.8 mm Hg...
please answer both. I just need these two last questions and
there due at midnight.
Oxygen gas can be prepared by heating potassium chlorate according to the following equation 2KCIO3(s) *2KCI(s) + 302(g) The product gas, O2, is collected over water at a temperature of 25 °C and a pressure of 747 mm Hg. If the wet O2 gas formed occupies a volume of 6.91 L, the number of grams of O, formed is g. The vapor pressure of water...
Use the References to access important values if needed for this question. Aluminum reacts with aqueous sodium hydroxide to produce hydrogen gas according to the following equation: 2Al(s) + 2NaOH(aq) + 6H20(1)—>2NaAl(OH)4(aq) + 3H2(g) The product gas, H,, is collected over water at a temperature of 20 °C and a pressure of 749 mm Hg. If the wet H, gas formed occupies a volume of 6.55 L, the number of grams of H, formed is g. The vapor pressure of...
Review Topics] References Use the References to access important values if needed for this question. Zinc metal reacts with excess hydrochloric acid to produce hydrogen gas according to the following equation: Zn(s) + 2HCl(aq) ZnCl(aq) + H2(8) The product gas, Hy, is collected over water at a temperature of 25 °C and a pressure of 755 mm Hg. If the wet Hy gas formed occupies a volume of 8.44 L, the number of moles of Zn reacted was mol. The...
24. Potassium chlorate (KCIO3) was heated to give oxygen. 2KCIO3 (s) - 2KCI (s) + 202 (g) A volume of 550mL of gas was collected over water at 21°C and an atmospheric pressure of 743 Torr. The vapor pressure of water at 21°C is 19 Torr. How many moles of oxygen were collected?
The thermal decomposition of potassium chlorate can be used to produce oxygen in the laboratory 2KCIO3 (8) ► 2KCI (s) + 302 (9) What volume (L) of O2 gas at 25°C and 1.00 atm pressure is produced by the decomposition of 7.5 g of KClO3 (s)? Select one: a. 11 b.4.5 CO d. 3.7 e. 2.3
[References Use the References to access important values if needed for this question The vapor pressure of ethanol is 54.68 mm Hg at 25°C. How many grams of saccharin, CH.NO,S, a nonvolatile, nonelectrolyte (MW - 183.2 g/mol), must be added to 282.3 grams of ethanol to reduce the vapor pressure to 54.01 mm Hg? ethanol - CH,CH,OH - 46.07 g/mol. g Saccharin
(3) Potassium chlorate (KCIO3) is known to decompose into potassium chloride (KCl) and oxygen gas (O2) upon heating: 2KCIO3 → 2KCl + 302 Suppose 10.0g of potassium chlorate is heated to complete decomposition. What is the volume of oxygen gas produced at room temperature (25°C) and atmospheric pressure (1.00 atm)? {R = 0.0821 L'atm/K mol}
Oxygen gas can be prepared in the laboratory by heating potassium chlorate, so that it decomposes according to the equation: What would the pressure of O2 be in a 2.50 L glass container at 220°C if 6.50 g of KCIO3 is decomposed? Multiple Choice 0.0796 atm 178 atm 662 atm < Prev 6 of 16 Nht >
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do i solve this?
1. A TA in Chemistry 111B prepares pure oxygen by heating solid potassium chlorate: KCIO3(s) →KCI (1) If the oxygen is collected over water at 22 C and a total pressure of 755 mm Hg, how many grams of KCIO3 would have to react to produce 2.00 L of wet gas? VP H2O = 20 mm Hg at 22 C.