Oxygen gas can be prepared in the laboratory by heating potassium chlorate, so that it decomposes...

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(3) Potassium chlorate (KCIO3) is known to decompose into potassium chloride (KCl) and oxygen gas (O2)...

(3) Potassium chlorate (KCIO3) is known to decompose into potassium chloride (KCl) and oxygen gas (O2) upon heating: 2KCIO3 → 2KCl + 302 Suppose 10.0g of potassium chlorate is heated to complete decomposition. What is the volume of oxygen gas produced at room temperature (25°C) and atmospheric pressure (1.00 atm)? {R = 0.0821 L'atm/K mol}
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Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s) . The equation for the reaction is 2KClO3⟶2KCl+3O2 Calculate how many grams of O2(g) can be produced from heating 70.4 g KClO3(s) STRATEGY: Convert the mass of KClO3 to moles. Convert the number of moles of KClO3 to the number of moles of O2 . Convert the number of moles of O2 to grams. Step 1: 70.4 g KClO3 is equal to 0.574 mol KClO3...
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