The thermal decomposition of potassium chlorate can be used to produce oxygen in the laboratory 2KCIO3...
The thermal decomposition of potassium chlorate can be used to produce oxygen in the laboratory. 2 KCIO3 (s) --> 2 KCl (s) + 3 O2 (9) What volume (L) of O2 gas at 25°C and 1.00 atm pressure is produced by the decomposition of 7.5 g of KClO 3 (s)? Select one: 0 a. 2.2 L O O O b. 4.5 L C. 11 d. 7.5 L e. 3.7 L
(3) Potassium chlorate (KCIO3) is known to decompose into potassium chloride (KCl) and oxygen gas (O2) upon heating: 2KCIO3 → 2KCl + 302 Suppose 10.0g of potassium chlorate is heated to complete decomposition. What is the volume of oxygen gas produced at room temperature (25°C) and atmospheric pressure (1.00 atm)? {R = 0.0821 L'atm/K mol}
24. Potassium chlorate (KCIO3) was heated to give oxygen. 2KCIO3 (s) - 2KCI (s) + 202 (g) A volume of 550mL of gas was collected over water at 21°C and an atmospheric pressure of 743 Torr. The vapor pressure of water at 21°C is 19 Torr. How many moles of oxygen were collected?
Potassium chlorate (KCIO3) is often used to generate oxygen according to its decomposition reaction (shown below): A.9 2KCI (s) +302(g) 2KCIO3(s) AH (kJ mol) S (JK mol) KCIO3 (s) KCI (s) 397.8 143.1 -435.9 82.6 O2 (g) 0 205.0 Use the thermochemical data provided above to calculate the standard change in Gibbs Energy (AG for this reaction at a temperature of 298K AH 88.6 kJ (A) 4G. AH-TOs (B) -88.6 kJ (C) -223.4 kJ (D) +223.4 kJ (E) 266.1 kJ...
Use the References to access important values if needed for this question. Oxygen gas can be prepared by heating potassium chlorate according to the following equation: 2KCIO3(s)— 2KCI(s) + 302(g) The product gas, 02, is collected over water at a temperature of 25 °C and a pressure of 747 mm Hg. If the wet O2 gas formed occupies a volume of 6.24 L, the number of grams of O2 formed is g. The vapor pressure of water is 23.8 mm...
What is the volume of oxygen gas released in the decomposition of 35.62 g of potassium chlorate at STP? KClO3 (s) ---> KCl (s) + O2 (g)
Percentage of Oxygen in Potassium Chlorate Introduction: The thermal decomposition of potassium chlorate can be described by the following equation: 2 KCIO3(s) 2 KCls) + 3 O2(g) Egn 1 (D stands for heating, elevated temperature) In this experiment you will determine the percentage of oxygen in potassium chlorate. You will compare the experimental result with the theoretical percentage calculated from the formula KCIO3. While potassium chlorate decomposes simply by heating, the reaction is very slow. A catalyst is used. Catalyst...
Oxygen gas can be prepared in the laboratory by heating potassium chlorate, so that it decomposes according to the equation: What would the pressure of O2 be in a 2.50 L glass container at 220°C if 6.50 g of KCIO3 is decomposed? Multiple Choice 0.0796 atm 178 atm 662 atm < Prev 6 of 16 Nht >
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s). The equation for the reaction is 2KClO3⟶2KCl+3O2 Calculate how many grams of O2(g) can be produced from heating 98.6 g KClO3(s). mass:
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s). The equation for the reaction is 2KClO3⟶2KCl+3O2⟶2KCl+3O2 Calculate how many grams of O2(g) can be produced from heating 48.8 g KClO3(s).