Balanced chemical equation is:
KOH + CH3COOH ---> CH3COOK + H2O
Here:
M(KOH)=0.4573 M
V(KOH)=26.45 mL
V(CH3COOH)=62.7 mL
According to balanced reaction:
1*number of mol of KOH =1*number of mol of CH3COOH
1*M(KOH)*V(KOH) =1*M(CH3COOH)*V(CH3COOH)
1*0.4573*26.45 = 1*M(CH3COOH)*62.7
M(CH3COOH) = 0.1929 M
Answer: 0.1929 M
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