We can find the equation of the curve:
Let daily expenses=y
And day=x
At x=0 ,y=2000
Then it increases by 1000 at each additional day
Y=2000+1000x
To find the total expenses from day 4 to day 6,
We can use integration,.
Integration of the function
2000x+500*x^2=f(x)
The total expenses from day 4 to day 6 =f(6)-f(3)
f(6)=2000*6+500*6*6=12,000+18000=30,000
f(6)=2000*3+500*3*3=6000+4500=10,500
Total expenses from day 4 to day 6=30,000-10,500=19,500
Or you can calculate by calculating the squares under line from 3 to 6, each square is equal to 1000.
Squares=18 and 3 half= 19.5
Total expanses=19.5*1000=19,500
010305 A film crew spent seven days shooting a TV commercial. The graph below depicts their...
Blackboard Help Question Completion Status: 010304 A film crew spent seven days shooting a TV commercial. The graph below depicts their daily expenses: $10,000 $9,000 $8,000 (Daily expenses - $/day) $3,000 $2,000 $1,000 $0 2 3 4 5 6 (Day) What were their total expenses for day 4 of filming through day 67 Use geometric formulas to calculate your answer. Express your answer in integer amounts (no cents); do not include a currency sign or commas. --> A Moving to...