Question

Vinegar is a Solotion of acek acid in waler Lithi hydtoxide, LiOH sed +o delemne the acetic acid, HCH2 Con ceatration in the vinegac SlutionAo0 mL Sample of vinegar wa hioled ha 0.200 M LIOH selotion. The acid Sanple fequiced 10.00 mL of the base to reach the equivalence paitt Remembec the Lithi lon is usta Spectator ion thus net eauation con be rllen 11 + a. What was tthe Cotcentratian of acetic acid in the vinegar Soluhion b. what was the p of the Salution hen lo.00 mL of base was abed to he acetic acid Solutian the PH of tthe Solotion C.what uoas when 15.00 mL d the base has been added ? you May a5s0ne Hal Kw: 1.00x 10

Answer 1

z acenc atld (in vinegar moles moles Naon added z mxu) naon o 3oom x 12.00 ml x los Solution) z I 3.60 x 103 moles. (chycoon negar saluran moles (4cool volume of solution do x10 3 moles z 10 ml x 103 mm 0-300m. 20-360m Ž (4₂200 + HT Chycoon I o.3oom gox X 3 Ka ? 0-360x neglect ka clo Сси соб) Си со x Corp coon 2) x 2 (HTJ Jisxos xogo = 0.0025m. pi l og Cut) = -log Co-0025) 212.60 moles base added a 0.300m x 600ml x 103 ml 2 1.80 x 103 moles. chacoon ton chocoo +H2O I 360x103 moles Suxio moles o C -1.80 mmoles 1-80 mmoles +1-gommoles F 1-80 mmoles 1-80 mmoles. 6

Here (CH₂(00) both weak acid (CH₂COOH) & its conjugare Present, so solurion acts as buffer as (Chroom) [CH₂600) moles HA 2 moles A) 2 -tog C1-8x105) here a 14-74 (-) 15-oome Point so on from base added 7 after equivalence of excess cie son excess chicoo negligible 2 Toral moles - mole Сон) realted left Total volume 0-300m ( 15.00 - 12.00) mL 10-00 ML + 15.00 mL volume of chroom volume of base por pH 2 & a 0-0360 m. tog Co-0360) a 0 444 14- 0.444 2 13-556 2 13.56 2)