The ΔG°\' of the reaction is -6.220 kJ ·mol–1. Calculate the equilibrium constant for the reaction. (Assume a temperature of 25° C.)
T= 25.0 oC
= (25.0+273) K
= 298 K
ΔGo = -6.22 KJ/mol
ΔGo = -6220 J/mol
use:
ΔGo = -R*T*ln Kc
-6220 = - 8.314*298.0* ln(Kc)
ln Kc = 2.5105
Kc = 12.31
Answer: 12.31
The ΔG°\' of the reaction is -6.220 kJ ·mol–1. Calculate the equilibrium constant for the reaction....
The ΔG°\' of the reaction is -6.220 kJ ·mol–1. Calculate the equilibrium constant for the reaction. (Assume a temperature of 25° C.)
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