Calculate the value of the equilibrium constant for a reaction at standard conditions if ΔG°=2.8 kJ/mol.
More information is needed. |
||
1.13 |
||
0.32 |
||
-4.2 |
||
-1.13 |
We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
Calculate the value of the equilibrium constant for a reaction at standard conditions if ΔG°=2.8 kJ/mol....
The ΔG°\' of the reaction is -6.220 kJ ·mol–1. Calculate the equilibrium constant for the reaction. (Assume a temperature of 25° C.)
The ΔG°\' of the reaction is -6.220 kJ ·mol–1. Calculate the equilibrium constant for the reaction. (Assume a temperature of 25° C.)
A (aq)-->enzyme<--B (aq) The ΔG°\' of the reaction is -6.220 kJ ·mol–1. Calculate the equilibrium constant for the reaction. (Assume a temperature of 25° C.) What is ΔG at body temperature (37.0° C) if the concentration of A is 1.5 M and the concentration of B is 0.75 M?
Calculate the equilibrium constant under standard conditions (K’eq) when (delta)G0’ is -4.18 kJ/mol. Standard conditions are 298 K and a gas constant = 8.32 x 10^-3 kJ/mol K
A certain reaction has a ΔG value of 13.8 kJ/mol. What is the value of the equilibrium constant (K) for this reaction when the temperature is 295 K? What is the value of K at 305 K when ∆Go = -4.75 kJ/mol? Consider a process with ∆H = 37.6 kJ and ∆S = 99.5 J/K. At what temperature will this process be at equilibrium?
A certain reaction has a ΔG value of 13.8 kJ/mol. What is the value of the equilibrium constant (K) for this reaction when the temperature is 295 K?
The equilibrium constant for a reaction is 0.35 at 25 °C. What is the value of AG* (kj/mol) at this temperature? A. 2.6 B.-4.2 C. 220 D.4.2 E. More information is needed.
For an equilibrium reaction, ΔG = 0 kJ at 432.6 K. If the standard change in Gibb's free energy of this reaction is 0.344 kJ, what is the equilibrium constant?
5.The following reaction has a ΔG°'--61.9 kJ/mol at 25°C, Phosphoenolpyruvate (PEP) +H2O Pyruvate + Inorganic Phosphate (Pi) (a) Is the reaction favorable under standard biochemical conditions? Explain your answer. (b) What is the equilibrium constant (K) of this reaction at 25°C? In cells the direct hydrolysis of PEP rarely occurs. Rather, the hydrolysis of PEP and the reverse hydrolysis of ATP are coupled (c) w rite out the coupled reaction and determine its ΔG at 25°C The hydrolysis of ATP...
The equilibrium constant for a reaction is 0.48 at 25 c. What is the value of AG (k/mol) at this temperature Seleccione una: a. 4.2 b. 1.8 d. 150 e. More information is needed. The equilibrium constant for a reaction is 0.48 at 25 cl What is the value of AG /mob at this temperature Seleccione una: a. 4.2 b. 18 c. 4.2 d. 150 e. More information is needed.