For an equilibrium reaction, ΔG = 0 kJ at 432.6 K. If the standard change in Gibb's free energy of this reaction is 0.344 kJ, what is the equilibrium constant?
T = 432.6 K
ΔGo = 0.344 KJ/mol
ΔGo = 344 J/mol
use:
ΔGo = -R*T*ln Kc
344 = - 8.314*432.6* ln(Kc)
ln Kc = -0.0956
Kc = 0.9088
Answer: 0.909
For an equilibrium reaction, ΔG = 0 kJ at 432.6 K. If the standard change in...
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