A reaction has a an equilibrium constant of 7.8 x 10 at 286.0 K. Calculate the Gilbbs free energy change (in kJ)....
Calculate the change in Gibbs free energy at standard conditions (TSS) and the equilibrium constant for each of the following reactions. (a) CH4(g) + H2O(g) equilibrium reaction arrow CO(g) + 3 H2(g); ?H° = +205.9 kJ, ?S° = +214.7 J/K ?G° 141.9 Correct: Your answer is correct. kJ K (b) CaCO3(s) equilibrium reaction arrow CaO(s) + CO2(g); ?H° = +179.2 kJ, ?S° = +160.2 J/K ?G° 131.5 Correct: Your answer is correct. kJ K
A reaction has a standard free-energy change of -11.40 kJ mol-1(-2.725 kcal mol-1). Calculate the equilibrium constant for the reaction at 25°C.
A reaction has a standard free-energy change of –16.50 kJ mol-1(-3.944 kcal mol-1). Calculate the equilibrium constant for the reaction at 25 °C. Keq = _______
For an equilibrium reaction, ΔG = 0 kJ at 432.6 K. If the standard change in Gibb's free energy of this reaction is 0.344 kJ, what is the equilibrium constant?
For a certain chemical reaction, the standard Gibbs free energy of reaction is −141. kJ. Calculate the temperature at which the equilibrium constant K=3.6 x 10^25.
calculate equilibrium constant and free energy change please Calculate the cell potential, the equilibrium constant, and the free-energy change for Ca(s) + M12+ (aq)(1M) = Cap+ (aq)(1M) + Mn(3) given the following E' values: Ca2+ (aq) + 2e + Ca(8) E° = -1.50 V Mn2+ (aq) + 2e - →Mn(s) E° = -0.58 V Part A Calculate the cell potential 0.920 V Previou Correct Part B Calculate the equilibrium constant I ALCO ? Submit Previous Answers Request Answer X Incorrect;...
Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: Ca2+(aq) + 2Cut (aq) *C(s) + 2Cu2+(aq) Answer: K for this reaction would b than one. greater less Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: ca2+(aq) + 2Cu(aq)+Ca(s) + 2Cu2+(aq) kJ K for this reaction would b than one. greater Answer: less Use standard reduction potentials to calculate the standard free energy change in kJ...
Calculate the equilibrium constant from the standard free energy change. Using standard thermodynamic data (linked), calculate the equilibrium constant at 298.15 K for the following reaction. H2(g) + Cl2(g)—>2HCI(g) K=
Calculate the equilibrium constant K and the standard free energy change ΔrG˚ at room temperature for the following reaction, HF(aq) H+(aq) + F- (aq) At equilibrium, you measured the following concentrations of reactants and products: [HF]eq = 0.092 M, [H+] eq = 0.008M, [F- ] eq = 0.008 M Think about it: According to your calculation of ΔrG˚, is this reaction reactant favored or product favored? Do you come to the same conclusion when you look at the equilibrium...
Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: 2Cu2+(aq) + Ni(s)2Cu+(aq) + Ni2+(aq) Answer: kJ K for this reaction would be _________ than one. Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: Sn2+(aq) + Cu(s) Sn(s) + Cu2+(aq) Answer: kJ K for this reaction would be _________ than one.